Second Order Kinetics Half Life

Question

A particular reaction is found to be second order. The reactant has an initial concentration of 2.19 M and a rate constant of 0.00870 M−1s−1. Calculate the half life of this reactant in seconds.

I know the formula is (T_1/2 = 1/k[A]_i) but I think I am getting the math mixed up somewhere.

Answer 1

Yes, the t_1/2 = 1/k[A]o

The math is as follows:

t_1/2 = 1 / (0.00870 M^-1s^-1 * 2.19 M) = 1 / 0.0191 s^-1) = 52.5 s