Raymond B. answered 06/01/21
Math, microeconomics or criminal justice
x^2 +4x + 3 = 0
(x+3)(x+1) = 0
x =-1, -3
x= -b/2a + or - (1/2a) sqr(b^2 -4ac) a=1, b=4, c=3
x= -4/2 + or - (1/2)sqr(16-12) = -2 + or - (1/2)sqr4 = -2 + or - 1 = -1, -3
x= -1, -3
Raymond B. answered 06/01/21
Math, microeconomics or criminal justice
x^2 +4x + 3 = 0
(x+3)(x+1) = 0
x =-1, -3
x= -b/2a + or - (1/2a) sqr(b^2 -4ac) a=1, b=4, c=3
x= -4/2 + or - (1/2)sqr(16-12) = -2 + or - (1/2)sqr4 = -2 + or - 1 = -1, -3
x= -1, -3
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