What quantity of heat (in kJ) is absorbed in the process of making 0.771 mol of CF₄ from the following reaction?

Question

C (s) + 2 F₂ (g) → CF₄ (g) ∆H° = 141.3 kJ/mol

Answer 1

From the equation provided, we see that 141.3 kJ of heat is absorbed for each 1 mol of CF4 produced.

Thus...

0.771 mol CF4 x 141.3 kJ / mol = 108.9 kJ of heat absorbed