Inactive Tutor answered 05/31/21
p (148.3 < X < 159.5)
On a TI-84 :
normalcdf
lower = 148.3
upper = 159.5
mean = 156.9
sd = 92.2
p (148.3 < M < 159.5)
mean is distributed normally, with mean = 156.9 , sd = 92.2 / √195
use the normalcdf
Brie L.
asked 05/31/21A population of values has a normal distribution with μ=156.9 and σ=92.2. You intend to draw a random sample of size n=195.
Find the probability that a single randomly selected value is between 148.3 and 159.5.P(148.3 < X < 159.5)
Find the probability that a sample of size n=195 is randomly selected with a mean between 148.3 and 159.5.P(148.3 < M < 159.5)
Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Inactive Tutor answered 05/31/21
p (148.3 < X < 159.5)
On a TI-84 :
normalcdf
lower = 148.3
upper = 159.5
mean = 156.9
sd = 92.2
p (148.3 < M < 159.5)
mean is distributed normally, with mean = 156.9 , sd = 92.2 / √195
use the normalcdf
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Brie L.
Thank You so much!05/31/21