Nivyan M. answered 06/03/21
10+ Years of Chemistry Tutoring Experience including Chemistry Lab TA
The first step will be to write out the chemical equation of the reaction and then balancing it. Next step would be to find the limiting reactant - in this case, it would be BaO2 (barium peroxide). After calculating, you would find that the amount of hydrogen peroxide produced is 0.224 g.
BaO2 + 2HCl -> BaCl2 + H2O2
1.12 g BaO2 x 1 mol BaO2/169.33 g BaO2 x 1 mol H2O2/1 mol BaO2 x 34.01 g H2O2/1 mol H2O2 = 0.224 g H2O2
Hope that helps!