Nivyan M. answered 06/03/21
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The first step will be to write out the chemical equation of the reaction and then balancing it. Next step would be to find the limiting reactant - in this case, it would be BaO2 (barium peroxide). After calculating, you would find that the amount of hydrogen peroxide produced is 0.224 g.
BaO2 + 2HCl -> BaCl2 + H2O2
1.12 g BaO2 x 1 mol BaO2/169.33 g BaO2 x 1 mol H2O2/1 mol BaO2 x 34.01 g H2O2/1 mol H2O2 = 0.224 g H2O2
Hope that helps!