J.R. S. answered 05/30/21
Ph.D. University Professor with 10+ years Tutoring Experience
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O ... balanced equation
moles NaOH needed = 0.0068 L x 6.0 mols/L = 0.0408 moles
moles H2SO4 present = 0.0408 mols NaOH x 1 mol H2SO4 / 2 mols NaOH = 0.0204 mols H2SO4
Concentration of H2SO4 = 0.0204 mols / 0.6000 L = 0.034 M (answer C)