Raymond B. answered 06/29/25
Tutor
5
(2)
Math, microeconomics or criminal justice
Pr(x) = 1/6 for x =1 through 6
Pr(1)=Pr(2)=Pr(3)=Pr(4)=Pr(5)=Pr(6) = 1/6
sum of all probabilities of all mutually exclusive disjoint outcomes = 1 = 6 x 1/6