Examine the following reaction equation and fill in the blanks

Question

KBr+ Cl₂→ KCl + Br₂

1-What is the oxidizing agent?

2-What is oxidized?

3-What is reduced?

4-What is reducing agent?

Answer 1

Look at oxidation numbers.

K on the left has ox.no. of 1+

K on the right has ox.no. of 1+

Br on the left has ox.no. of 1-

Br on the right has ox.no. of zero (it has been oxidized, i.e. lost electrons)

Cl on the left has ox.no. of zero

Cl on the right has ox.no. of 1- (it has been reduced, i.e. gained electrons)

1). oxidizing agent = Cl₂

2). Br is oxidized

3). Cl (Cl₂) is reduced

4). reducing agent = Br