J.R. S. answered 05/28/21
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∆H = 4.68 kJ/º x 11.23º = 52.56 kJ
moles of thymol = 1.397 g x 1 mol / 150 g = 0.009313 moles
Heat of combustion, in kJ/mole = 52.56 kJ / 0.009313 mols = 5644 kJ/mole