I will not give you every step of the 2 column proof, but if you follow what I give you, you should be able to write it completely.
Because of the parallelograms and KJ=KM, triangles AJK,KJM and MBK are all isosceles and congruent.
That makes angles JAK and KBM equal (corresponding parts of congruent triangles)
Therefore ABC is isosceles.