
Yefim S. answered 05/26/21
Math Tutor with Experience
(5sinA - cosA)/(12sinA - 13cosA) = (5tanA - 1)/(12tanA - 13) = (5·12/5 - 1)/(12·12/5 - 13) = 11/(144/5 - 13) =
= 55/(144 - 65) = 55/79
Maryam A.
asked 05/26/21If tan A = 12/5 (fraction) and A is acute, find the value of 5sinA - cosA/12sinA-13cosA
Yefim S. answered 05/26/21
Math Tutor with Experience
(5sinA - cosA)/(12sinA - 13cosA) = (5tanA - 1)/(12tanA - 13) = (5·12/5 - 1)/(12·12/5 - 13) = 11/(144/5 - 13) =
= 55/(144 - 65) = 55/79
Raymond B. answered 05/26/21
Math, microeconomics or criminal justice
It's a 5-12-13 right triangle with hypotenuse =13
sinA =12/13
cosA = 5/13
5sinA = 60/13
12sinA = 144/13
13cosA = 65/13
5sinA-cosA/12sinA -13cosA = 60/13 - 5/144 - 65/13 = -5/13 -5/144 = -720/1872- -9360/1872 =- 10080/1872 =about 5.4
UNLESS you really meant (5sinA-cosA)/(12sinA-13cosA)
then
(60/13 -5/13)/(144/13-65/13) = (55/13)/(79/13 = 55/79
Odds are you want 55/79
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