Chem 30 - The Constant Equilibrium

Question

Once you have balanced the following chemical equation, choose the correct corresponding equilibrium law expression:

Ag₂CO_3(s)  ↔ Ag_(s)  + CO_2(g)  + O_2(g) 

Kc=?

Once you have balanced the following chemical equation, choose the correct corresponding equilibrium law expression:

C₃H₈ (g) + O₂(g) ßà CO₂(g) + H₂O(g)

Kc=?

Once you have balanced the following chemical equation, choose the correct corresponding equilibrium law expression:

 HgO_(s) ↔ Hg_(l) + O_2(g)

Kc=?

Write an equilibrium law expression for the following word equation:

Dissolving solid barium hydroxide in water.

Kc=?

Write an equilibrium law expression for the following word equation:

ammonia gas and hydrogen chloride gas react to form solid ammonium chloride

Kc=?

Determine the equilibrium constant for the reaction below given the following concentrations at equilibrium:

     2 H₂S(g) ↔  2 H₂(g) + S₂(g)

1. [H₂S]= 0.23 mol/L
2. [H₂]= 0.81 mol/L
3. [S₂] = 0.40 mol/L

K_c= a.bc ie 3 digit answer including decimal

Determine the equilibrium constant for the reaction below given the following concentrations at equilibrium:

NO_2(g) + CO_(g) ↔  NO_(g) + CO_2(g)

1. [NO₂]= 0.043 mol/L
2. [CO]= 0.031 mol/L
3. [NO] = 1.8 mol/L
4. [CO₂] = 2.1 mol/L

K_c= abcd  ie 4 digit answer

0.450 mol of hydrogen bromide gas decomposes in a 0.75 L container according to the reaction below:

2 HBr_(g)  ↔ H_2(g) +  Br_2(l)

At equilibrium the concentration of H_2(g) was found to be 0.132 mol/L. The value of the equilibrium constant Kc is a.bc

Initially 0.500 mol/L NOCl(g) reaches equilibrium as shown in the equation below:

2 NOCl_(g) ↔ Cl_2(g)  + 2 NO_(g)

At equilibrium concentration of Cl₂(g) is 0.14 mol/L. 

The value of the equilibrium constant Kc is a.bc

Initially 0.105 mol/L of N₂O_4(g) is placed in a flask and allowed to reach equilibrium as shown in the reaction below:

N₂O_4(g) ↔   2 NO_2(g)

At equilibrium the concentration of N₂O₄ was found to be 0.071 mol/L. At equilibrium, the concentration of NO₂ is a.bcd

Answer 1

I will do one or 2 just to show you the process. There are way too many for me to spend that amount of time answering all of them.

2Ag₂CO_3(s)  ↔ 4Ag_(s)  + 2CO_2(g)  + O_2(g) 

Kc= [CO₂]²[O₂] ... note that solids are not included in the equilibrium expression

C₃H₈ (g) + 5O₂(g) <->3 CO₂(g) + 4H₂O(g)

Kc = [CO₂]³[H₂O]⁴ / [C₃H₈][O₂]⁵