A ball is thrown into the air. Its height h in meters after t seconds is given by the equation.

Question

h = -5(t - 2)² + 25

How high up will the ball be in 1 second?

Answer 1

h(t) = -5(t-2)^2 + 25

at time t=1

h(1) = -5(1-2)^2 + 25 = -5+25 = 20 meters high after 1 second

Answer 2

h(t) = -5(t-2)^2 + 25

at time t=1

h(1) = -5(1-2)^2 + 25 = -5+25 = 20 meters high after 1 second