
Yefim S. answered 05/24/21
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2sin2xcosx - cosx = 0; cosx(2sin2x - 1) = 0; cosx = 0; x = π/2 or x = 3π/2
2sin2x - 1 = 0; - cos2x = 0; cos2x = 0; 2x = π/2 or 3π/2 or 5π/2 or 7π/2
x = π/4 or 3π/4 or 5π/4 or 7π/4