
Billy M. answered 05/24/21
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The given equation is
y''+ 64y = 0
Which is a second order homogeneous ODE. The characteristic equation corresponding to this ODE is
r^2 + 64 = 0
r = 8i, -8i
So, the solution is
y=C1sin(8x)+C2cos(8x)
which implies
y = C1sin(8x)+C2cos(8x)
y '= 8C1cos(8x)-8C2sin(8x)
Using the condition y'(0) = 1, we get C1 = 1/8
Finally, using the condition y(0) = 1, we get C2 = 1
Therefore, the solution is
y = cos(8x) + 1/8sin(8x)