C++ question Pritty’s Program

Question

Pritty’s Program

After going through the problem-solving process

Pritty finally arrived at this stage; the one just before she begins to write the code.

PLAN 1,

Write a message politely asking the user to enter values for ResONE, ResTWO and ResTHREE

2. Enter the corresponding values for those variables.

3. Set InvResONE to 1/ResONE (Inverse of ResONE)

4. Set InvResTWO to 1/ResTWO (Inverse of ResTWO)

5. Set InvResTHREE to 1/ResTHREE (Inverse of ResTHREE)

6. Set InvResTOT to (InvResONE + Inv ResTWO + InvResTHREE)

7. Set ResTOT to 1/InvResTOT

8. Print ResTOT

TASK

a) Draw a possible Structure Chart for the Plan (1-8) above

b) Write a C++ program based on Pritty’s Plan (1-8) above

c) Compile, Run and check using different values.

Answer 1

using namespace std;

#include <iostream>

#define EPSILON (0.00000000001) //good to 10 digits

double InputResValue(char * strMsgPrompt=NULL)

{

double resVal=0;

while (resVal<EPSILON)

{

if (strMsgPrompt==NULL)

{

cout << "Please input the number :>";

}

else

{

cout << strMsgPrompt << " :>";

}

cin >> resVal;

}

return(resVal);

}

Go()

{

double resONE=0, resTWO=0, resTHREE=0;

resONE = InputResValue("Please input the 1st number :>");

resTWO = InputResValue("Please input the 2nd number :>");

resTHREE = InputResValue("Please input the 3rd number :>");

resONE = 1/resONE;

resTWO = 1/resTWO;

resTHREE = 1/resTHREE;

double InvResTOT = resONE + resTWO + resTHREE;

if (InvResTOT > EPSILON)

{

InvResTOT = 1/InvResTOT;

cout << InvResTOT << endl;

}

else

{

cout << " DIVISION BY ZERO EXCPETION " << endl;

}

}

int main()

{

Go();

}