
Sidney P. answered 05/19/21
Astronomy, Physics, Chemistry, and Math Tutor
Make a sketch with a point at x = -2, y = -3, thereby lying in quadrant III. Draw a line from the negative x-axis down to this point, constructing a right triangle. The hypotenuse is then √13. cos θ = -2 /√13 = -2 √13 /13.
csc θ = 1/sin θ = - √13 /3. tan θ = (-3) /(-2) = 3/2.