In a titration 0.452L of 0.95M barium hydroxide is used to neutralize 15.5mL of sulfuric acid. What is the concentration of sulfuric acid?

Answer 1

Ba(OH)₂ + H₂SO₄ ==> BaSO₄ + 2H₂O ... balanced equation

moles Ba(OH)₂ used = 0.452 L x 0.95 mol/L = 0.4294 mols

moles H₂SO₄ present = 0.4294 because they react in a 1:1 mol ratio according to the balanced equation

molarity of H₂SO₄ = mols/liters

moles = 0.4294

liters = 15.5 ml x 1 L/1000 ml = 0.0155 L

Molarity (M) = 0.4294 mols / 0.0155 L = 27.7 M