J.R. S. answered 05/18/21
Ph.D. University Professor with 10+ years Tutoring Experience
CaCO3 ==> CO2 + CaO ... balanced equation
40 g CO2 x 1 mol CO2 / 44 g = 0.909 moles CO2 formed
moles CaCO3 present = 0.909 mols CO2 x 1 mol CaCO3 / mol CO2 = 0.909 mols CaCO3
Estimated mass of CaCO3 present = 0.909 mols CaCO3 x 100 g / mol = 90.9 g CaCO3 (~91%)