The equilibrium constant for a certain reaction is found to be 2.0x10⁴ at a certain temperature. What is the value of the equilibrium constant for the reverse reaction?

Answer 1

The equilibrium constant for a reverse reaction is the reciprocal of the equilibrium constant for the forward reaction. So, in the current problem you have K' = 1/K = 1 / 2.0x10⁴ = 5x10^-5