If I have 37 moles of gas at a pressure of 91 kPa and at a temperature of 126 0C, what is the volume of the container that the gas is in?

Answer 1

Ideal gas law: PV = nRT

P = pressure

V = volume

n = moles

R = gas constant

T = temperature

To use this equation, we have to keep our units consistent. The units of R will dictate what units of pressure we use. To use the familiar R = 0.0821, the units are L-atm / Kmol so pressure has to be in atmospheres, volume in liters, and temperature in Kelvin. So, let us convert 91 kPa to atm, and 126ºC to Kelvin. Our answer will then be volume in liters.

91 kPa x 1 atm/101.325 kPa = 0.898 atm

126ºC + 273 = 399K

Substituting the values into the ideal gas law and solving for V we have...

V = nRT/P = (37 mols)(0.0821 Latm/Kmol)(399K) / 0.898 atm

V = 1350 liters