J.R. S. answered 05/17/21
Ph.D. University Professor with 10+ years Tutoring Experience
Your response seems to be correct. Since an elevated temperature reduces the Keq, this suggests the reaction is exothermic and thus ∆H is negative @ 25ºC.
Gahij G.
asked 05/17/21Sr2+(aq) + F-(aq) ⇄ SrF+(aq)
At 25°C, the equilibrium constant for the reaction represented above has a value of 1.3. At 50°C, the value of the equilibrium constant is less than 1.3. Based on this information, which of the following must be correct?
is this correct?
J.R. S. answered 05/17/21
Ph.D. University Professor with 10+ years Tutoring Experience
Your response seems to be correct. Since an elevated temperature reduces the Keq, this suggests the reaction is exothermic and thus ∆H is negative @ 25ºC.
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