is this correct

Question

Fe²⁺(aq)+Zn(s)→Fe(s)+Zn²⁺(aq)E°cell=+0.32V

A galvanic cell generates a cell potential of +0.32V when operated under standard conditions according to the reaction above. Which of the following pairs of conditions are needed to construct a similar cell that generates the highest cell potential?

1. [Zn²⁺]=2M and [Fe²⁺]=1M because Q<1.

1. [Zn²⁺]=0.25M and [Fe²⁺]=1M because Q<1.

1. [Zn²⁺]=1M and [Fe²⁺]=2M because Q>1.

1. [Zn²⁺]=2M and [Fe²⁺]=0.5M because Q>1.

is this correct

Answer 1

I think your answer is not correct. According to the Nernst equation, in order for Ecell to be larger than the standard cell potential, Q should be <1 so that the log of Q is negative, and thus Eº - log Q will be greater than Eº.

Nernst: Ecell = Eº - RT/nF ln Q or at 298K, we have Ecell = Eº - 0.0596/n log Q

The highest cell potential would be obtained when Q has the lowest value, i.e. when [Zn²⁺]/[Fe²⁺] is smallest

1.  [Zn²⁺]=0.25M and [Fe²⁺]=1M because Q<1 seems like the correct response