is this correct

Question

M(s) + 3 Ag⁺(aq) → 3 Ag(s) + M³⁺(aq)    E° = + 2.06 V

Ag⁺(aq) + e^- → Ag(s)                   E° = + 0.80 V

According to the information above, what is the standard reduction potential for the half-reaction M³⁺(aq) + 3 e^- → M(s) ?

1. -1.26 V

1. +1.26 V

1. -1.66 V
2. 1.66 V

is this correct

Answer 1

I believe the answer should be -1.26V. My reasoning is as follows:

The reduction half reaction is 3Ag⁺(aq) + 3e- ==> 3Ag(s) ... this would be the cathode

The oxidation half reaction is M(s) ==> M³⁺(aq) + 3e- ... this would be the anode

Cell potential = reduction potential at cathode - reduction potential at anode

Since Eºcell = 2.06 V, the standard reduction potential for M³⁺ + 3e- would have to be -1.26 V

0.80 V - x V = +2.06 V

-x V = 2.06 V - 0.80 V = 1.26 V

x = -1.26 V