J.R. S. answered 05/16/21
Ph.D. University Professor with 10+ years Tutoring Experience
Use the ideal gas law to find the moles of sulfur dioxide. Then use the fact that at STP, 1 mole of gas occupied 22.4 liters.
PV = nRT
P = 720 mm Hg x 1 atm / 760 mm Hg = 0.947 atm
V = 652 ml = 0.652 L
n = ?
R = 0.0821 Latm/Kmol
T = 40º + 273 = 313K
Solving for n, we have...
n = PV/RT = (0.947)(0.652) / (0.0821)(313)
n = 0.0240 moles SO2
At STP..
0.0240 mols x 22.4 L/mol = 0.538 L = 538 mls