Samantha wants to neutralize 1.21 L of 0.102 M KOH with 0.101 M HNO3. Show all calculations for the following questions.

Question

a) Write a balanced equation for this reaction. 

b) What is the mole ratio between KOH and HNO₃?

c) How many moles of KOH  are present in 1.21 L of 0.102 M KOH solution?

d) How many moles of HNO₃ are required to neutralize 1.21 L of 0.102 M KOH solution?

e) What volume of 0.101 M HNO₃ is required to neutralize 1.21 L of 0.102 M KOH solution?

Answer 1

a) KOH + HNO3 ==> H2O + KNO3 ... balanced equation

b) 1 : 1 is the mol ratio

c) 1.21 L x 0.102 mol/L = 0.123 moles

d) 0.123 moles of HNO3 are required

e) (x L)(0.101 mol/L) = 0.123 moles

x = 1.22 L will be required