J.R. S. answered 05/15/21
Ph.D. University Professor with 10+ years Tutoring Experience
(1).
P1 = 742 torr
V1 = 500 ml
T1 = 20º + 273 = 293K
P2 = 805 torr
V2 = ?
T2 = 293K
Constant temperature = Boyle's Law: P1V1 = P2V2
(742 torr)(500 ml) = (805 torr)(V2)
V2 = 471 mls
(2).
V1 = 7.2 L
P1 = ?
V2 = 25.1 L
P2 = 1.75 atm
Assume constant temperature since none is provided. This again is Boyles Law: P1V1 = P2V2
(P1)(7.2 L) = (1.75 atm)(25.1 L)
P1 = 6.10 atm