Syeda Aaliya F. answered 05/15/21
Holistic Mathematics Tutor
line points (-3 ,9) and (3 , -1) .
slop = y2 - y1/x2-x1 = -1-9/3- -3 = -10/6 = -5/3
y= mx + c
y = -5/3 x + c
-1 = -5/3 • 3 + c
-1+5 = c
c=4
y= -5/3x + 4
3y=-5x+12
5x +3y = 12
Alyssa Z.
asked 05/14/21Find an equation of the line described. Leave the solution in the form Ax + By = C.
The line contains (−3, 9) and (3, −1).
Syeda Aaliya F. answered 05/15/21
Holistic Mathematics Tutor
line points (-3 ,9) and (3 , -1) .
slop = y2 - y1/x2-x1 = -1-9/3- -3 = -10/6 = -5/3
y= mx + c
y = -5/3 x + c
-1 = -5/3 • 3 + c
-1+5 = c
c=4
y= -5/3x + 4
3y=-5x+12
5x +3y = 12
Raymond B. answered 05/15/21
Math, microeconomics or criminal justice
(-3,9), (3,-1)
the line through the points has slope = m = (9--1)/(-3-3) = -10/6 =-5/3
y = mx + b
y= -5x/3 + b
-1=-5(3)/3 + b
b = -1+5 = 4
y=-5x/3 +4
3y =-5x +12
5x + 3y = 12 A=5, B=3, C=12
Mark M. answered 05/14/21
Mathematics Teacher - NCLB Highly Qualified
Use two-point form (from Algebra 1)
(y - 9) / (x + 3) / (-1 -9) / (3 + 3)
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