Find three consecutive integers such that the first integer is four more than six times the third

Answer 1

let the 3 integers be x-1, x, and x+1

x-1 = 4 + 6(x+1)

x-1 = 4+6x + 6

5x = -11

x =-11/5 is not an integer

maybe you have a typo and meant 3, not 4 more than 6 times the 3rd?

3 and 4 are close on the keyboard. if so,

then

x-1 = 3 + 6(x+1)

x-1 = 3+6x +6

5x =-10

x =-2

the number are -3,-2 and -1

first is 3 more than 6 times the 3rd

-3 = 3+ 6(-1)=3-6=-3