How many mL of strong 17.5 M nitric acid will i need to make 500 mL of a 2.5 M weaker solution?

Answer 1

V1M1 = V2M2

V1 = initial volume = ?

M1 = initial concentration = 17.5 M

V2 = final volume = 500 ml

M2 = final concentration = 2.5 M

(x ml)(17.5 M) = (500 ml)(2.5 M)

x = 71.4 mls