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Question

The distance formula is given by the equation 𝑑=(𝑥2−𝑥1)2+(𝑦2−𝑦1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√d=(x2−x1)^2+(y2−y1)^2

where d is the distance between the two points (x₁, y₁) and (x₂, y₂). 

Kevin graphed the points A(-4, 3), B(-2, 1), C(0, 4), and D(3, -5). Find AB + BC + CD rounded to the nearest tenth.

AB + BC + CD 

Answer 1

Hi Jose C.,

AB = √[(-2-(-4))² + (1-3)²] = √[4+4] = 2√[2]

BC = √[(0-(-2))² + (4-1)²] = √[4+9] = √[13]

CD = √[(3-0)² + (-5-4)²] = √[9+81] =√[90] =3√[10]

AB+BC+CD = 2√[2]+√[13]+3√[10]

I hope this helps, Joe.