need help with algebra

Question

1/ Write the coordinate point that is 5 units right of the y-axis and 3 units below the x-axis.

-5, -3)

(-3, 5)

(3, 5)

(5, -3)

2/ Solve the equation for z

w/x = y/z

3/ What is the slope of the line passing through the points (4, 8) and (9, 2).

4/In which quadrant does the ordered pair (-7, -1) lie?

5/ State the domain and range of the relation and determine whether the relation is a function.

{(-8, -6), (-5, 2), (-8, 1), (7, 3)}

Group of answer choices

D: {-8, -5, 7}

R: {-6, 1, 2, 3}

Not a function

D: {-6, 1, 2, 3}

R: {-8, -5, 7}

Function

D: {-8, -5, 7}

R: {-6, 1, 2, 3}

Function

D: {-6, 1, 2, 3}

R: {-8, -5, 7}

Not a function

Answer 1

(5,-3) is 5 to the right of x=0, and 3 below y=0. x=0 is the y axis, y=0 is the x axis

x=5 is to the right of x=0 by 5 units. y=-3 is 3 units below y=0

w/x =y/z cross multiply to get wz=xy, then divide both sides by w to get

x =xy/w

(4,8),(9,2)

line through those points has slope = (8-2)/(4-9) = 6/-5 = -6/5 = -1.2

slope is the "rise over run" or the difference in y coordinates divided by the difference in x coordinates. 8-2 divided by 4-9

(-7,-1) is in quadrant III. Only quadrant III has x<0 and y<0. In quadrant I, x and y are both positive. In quadrant II, y is positive but x is negative. In quadrant III both are negative. In quadrant IV, x is positive but y is negative.

1st choice, not a function because x=-8 has 2 y values due to the points (-8,-6) and (-8,1) IF you plot those two points on a graph, you can draw a vertical line through those two points. It's not a function if it is possible to draw a vertical line and intersect more than one point. It's called the "vertical line test"