At 25 °C, only 0.0360 mol of the generic salt AB3 is soluble in 1.00 L of water. What is the 𝐾sp of the salt at 25 °C?

Question

AB3(s)↽−−⇀A3+(aq)+3B−(aq)

Answer 1

AB₃(s) ==> A³⁺(aq) + 3B^-(aq)

Ksp = [A³⁺][B^-]³

0.0360 mol / liter = 0.0360 M AB₃

[A³⁺] = 0.0360 M

[B^-] = 3 x 0.0360 M = 0.108 M

Ksp = (0.0360)(0.108)³

Ksp = 4.53x10^-5