Calculate the heat gained by the cool water for copper, use the specific heat of water for this problem.

Question

mass of calorimeter (g)	2.50
mass of calorimeter & water(g)	84.02
mass of water (g)	81.52
mass of metal (g)	4.42
Ti of cool water (℃)	21.2
Ti of metal (℃)	101.0
Tf of water (℃)	22.0
Tf of metal (℃)	22.0
ΔT of water (℃)	0.8
ΔT of metal (℃)	-79

Answer 1

m = mass of water = 84.02 g - 2.50 g = 81.52 g

∆T = Change in temperature of the water = 22.0 - 21.2 = 0.8º

C = specific heat for water = 4.184 J/gº

q = heat

Use the equation q = mC∆T and solve for q:

q = (81.52 g)(4.184 J/gº)(0.8º)q = 273 J