What is the theoretical yield of iron when30 grams of aluminum are used in the reaction below? 2Al + 3FeO -->3Fe +Al₂O₃

Answer 1

atomic mass Al = 26.98 g/mol

atomic mass Fe = 55.85 g/mol

2Al + 3FeO ==> 3Fe + Al2O3 ... balanced equation

Since no mass is given for FeO, we can assume it to be in excess. Therefore the theoretical yield will depend on the amount (moles) of Al present,

Theoretical yield of Fe = 30 g Al x 1 mol Al / 26.98 g x 3 mols Fe / 2 mols Al x 55.85 g Fe / mol Fe = 93 g Fe