Heat calculation

Question

Calculate the specific heat of a metal if a 38 g sample of the metal was heated to 50° C and placed in 50.0g of water at 25°C. The final temperature of mixture was 28° C.

Answer 1

q = mC∆T where q = heat, m = mass, C = specific heat, ∆T = change in temperature

heat lost by metal = heat gained by water

(38 g)(C)(50º - 28º) = (50.0 g)(4.184 J/gº)(28º - 25)

836 g-degree x C = 627.6 J

C = specific heat of metal = 627.6 J/836 g-degree

C = 0.751 J/gº