math300 statistics

Question

Of the people who fished at Clearwater Park today, 56 had a fishing license, and 24 did not. Of the people who fished at Mountain View Park today, 81 had a license, and 9 did not. (No one fished at both parks.)

Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license?

Answer 1

The probability that the Clearwater angler is unlicensed is given by 24/(56+24).

The probability that the Mountain View angler is licensed is equal to 81/(9+81).

The probability that the Clearwater angler is unlicensed and the Mountain View

angler is licensed is given by 24/(56+24) times 81/(9+81) or (3/10)(9/10) or

"27 out of 100" chances.