2 Sin2X = 6 Cos2 X
Dividing by 2
Sin2X = 3 Cos2X
Divide by Cos2X
tan2 X = 3
tan X = √3
X = arc tan (√3 ) or tan-1 √3
X = 60 degree or pi/3 radian
Peyton L.
asked 05/11/21Solve the following equation
2 sin^2 x = 6 cos^2x
2 Sin2X = 6 Cos2 X
Dividing by 2
Sin2X = 3 Cos2X
Divide by Cos2X
tan2 X = 3
tan X = √3
X = arc tan (√3 ) or tan-1 √3
X = 60 degree or pi/3 radian
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.