J.R. S. answered 05/11/21
Ph.D. University Professor with 10+ years Tutoring Experience
3Pb2+(aq) + 6e- ==> 3Pb(s) ... reduction half reaction
2Cr(s) ==> 2Cr3+(aq) + 6e- ... oxidation half reaction
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3Pb2+(aq) + 2Cr(s) ==> 3Pb(s) + 2Cr3+(aq) ... redox reaction
Eºcell = -0.13 V + 0.74 V = +0.61 V (Answer e)
Faith L.
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