J.R. S. answered 05/11/21
Ph.D. University Professor with 10+ years Tutoring Experience
Any reaction with a reduction potential greater than -0.13 V will be preferentially reduced, thus oxidizing Pb2+.
So, that would be:
e) Cu2+
Faith L.
asked 05/11/21Given:
Pb2+(aq) + 2e– --> Pb(s); E° = –0.13 V
Zn2+(aq) + 2e– --> Zn(s); E° = –0.76 V
Al3+(aq) + 3e– --> Al(s); E° = –1.66 V
Mg2+(aq) + 2e– --> Mg(s); E° = –2.38 V
V2+(aq) + 2e– --> V(s); E° = –1.18 V
Cu2+(aq) + 2e– Cu(s); E° = 0.34 V
Which of the following cations is capable of oxidizing Pb to Pb2+ under standard-state conditions?
a. V 2+
b. Al 3+
c. Mg 2+
d. Zn 2+
e. Cu 2+
J.R. S. answered 05/11/21
Ph.D. University Professor with 10+ years Tutoring Experience
Any reaction with a reduction potential greater than -0.13 V will be preferentially reduced, thus oxidizing Pb2+.
So, that would be:
e) Cu2+
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