Consider the following cell reaction....

Question

Consider the following cell reaction:

2Hg²⁺(aq) + H₂(g) → 2H⁺(aq) + Hg₂²⁺(aq); E°_cell = 0.92 V



Under standard-state conditions, what is E° for the following half-reaction?

Hg²⁺(aq) + 2e^– → Hg₂²⁺(aq)

Answer 1

2Hg²⁺(aq) + 2e- ==> Hg₂²⁺(aq) ... reduction Eº = x

H₂(g) ===> 2H⁺ + 2e- ... oxidation Eº = 0 V

x - 0 = 0.92 V

x = +0.92V