J.R. S. answered 05/11/21
Ph.D. University Professor with 10+ years Tutoring Experience
#2 barium bromate would favor the products
Aluminum hydroxid = Al(OH)3
Al(OH)3(s) <==> Al3+(aq) + 3OH-(aq)
Ksp = 3x10-34 = [Al3+][OH-]3 = (x)(3x)3 = 27x4
x = molar solubility = 1.83x10-9 M
Ba(BrO3)2(s) <==> Ba2+(aq) + 2BrO3-(aq)
Ksp = 2.43x10-4 = [Ba2+][BrO3-]2 = (x)(2x)2 = 4x3
x = molar solubility = 3.93x10-2 M