i need help asap

Question

You have 1.5 M stock solution of HCI, Your experiment calls for a concentration of 3.36e-3M, which of the following is the correct procedure for achieving this concentration ?

1)Adding 100 mL of 1.5 NaOH to a volumetric flask and diluting to 4.2 L.

2)Adding 1.12 mL of 1.5 M NaOH to a volumetric flask and diluting to 500 mL.

3)Adding 2.0 mL of 1.5 M NaOH to a volumetric flask and diluting 1.0 L.

4)Adding 0.5 mL of 1.5 M NaOH to a volumetric flask and diluting to 100 mL

Answer 1

I have to assume you copied the problem incorrectly because the problem deals with HCl (1.5 M) but the answers deal with NaOH. I'll assume the answers should be HCl and not NaOH

This is a straight forward dilution problem and you can use M1V1 = M2V2. Applying this formula to the different options provided, we have the following:

1) (100 ml)(1.5 M) = (4200 ml)(x M) and x = 3.57x10^-2 M ... incorrect

2) (1.12 ml)(1.5 M) = (500 ml)(x M) and x = 3.36x10^-3 M ... CORRECT

No need to do the other calculations.