
Mark M. answered 05/10/21
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
2 = [tan A + tan B] / [1 - tan A tan B]
Can you substitute 1 / 3 for tan B and solve for tan A?
Savea M.
asked 05/10/21Mark M. answered 05/10/21
Mathematics Teacher - NCLB Highly Qualified
2 = [tan A + tan B] / [1 - tan A tan B]
Can you substitute 1 / 3 for tan B and solve for tan A?
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Savea M.
Yes05/10/21