Objective: Leap years as we know them began in 1582. You are going to create a program that allows the user to enter a year and be told whether it is a leap year or a common year.

Question

Specifications: 

1. When your program opens, give a brief description of what a leap year is and why we have them. 
2. Ask the user to enter a year.
3. You must use TryParse to determine if the user has entered a positive integer. If they do not, you must give them an error message and send them back to the beginning.

Assuming they entered an appropriate year: 

1. If they enter a number less than 1582, tell them to enter a more recent year. You can explain why in your error message.
2. If they enter a year between 1582 and 3000, tell them whether their year is a leap year or a common year.
3. If they enter a year greater than 3000, tell them not to look so far into the future.
4. Make the program continuous. (Be sure to clear at appropriate times.)

Answer 1

using System;

class LeapYear

{

static void Main()

{

String inbuff;

int year=0;

while (year<1583 || year>3000)

{

Console.Write(" Please input the year between 1583 and 3000 :>");

inbuff = Console.ReadLine();

year = Int32.Parse(inbuff);

}

Console.Write(" The year " + year);

if (year%400==0)

{

Console.WriteLine(" is a leap year. ");

}

else

{

if (year % 100==0)

{

Console.WriteLine(" is NOT a leap year. ");

}

else

{

if (year %4==0)

{

Console.WriteLine(" is a leap year.");

}

else

{

Console.WriteLine(" is not a leap year.");

} //year divisible by 4

} //year divisible by 100

} //year divisble by 400

} //Main

} //class