2C2H2 + 5O2 -> 4CO2 + 2H2O Identify theoretical yields in grams if 100.0 g of each reactant was used.

Question

2C2H2 + 5O2 -> 4CO2 + 2H2O

Identify theoretical yields in grams if 100.0 g of each reactant was used.

Answer 1

2C₂H₂ + 5O₂ -> 4CO₂ + 2H₂O

100 g C2H2 x 1 mol C2H2 / 26 g = 3.85 mols C2H2

100 g O2 x 1 mol O2 / 32 g = 3.125 mols O2

Limiting reactant = O2 because you need 2.5 times as much O2 as you do C2H5 but don' t have that much.

Theoretical yields of CO2 and H2O are as follows:

3.125 mols O2 x 4 mols CO2 / 5 mols O2 x 44 g CO2 / mol CO2 = 110 g CO2

3.125 mols O2 x 2 mols H2O /5 mols O2 x 18 g H2O / mol H2O = 22.5 g H2O