Hellppppp What volume (L) of 0.432 M NaOH is needed to titrate 50.0 mL of 0.254 M HCl? You must show your work to receive credit.

Question

1. What volume (L) of 0.432 M NaOH is needed to titrate 50.0 mL of 0.254 M HCl? You must show your work to receive credit.

Answer 1

First, write the balanced equation for the reaction taking place:

NaOH + HCl ==> NaCl + H2O ... balanced equation

(note the mole ratio of NaOH to HCl is 1:1)

moles HCl present = 50.0 ml x 1 L/1000 ml x 0.254 mols / L = 0.0127 mols HCl

moles NaOH present = 0.0127 mols since the mol ratio of NaOH : HCl is 1:1

Volume of NaOH needed to produce 0.0127 mols NaOH:

(0.432 mols/L) (x L) = 0.0127 mols

x = 0.0294 L