How many moles of V205 are consumed to produce 12.0 grams of oxygen?

Question

2V₂O₅(s) → 4V(s) + 5O₂(g)

Answer 1

2V₂O₅(s) → 4V(s) + 5O₂(g) ... balanced equation

12.0 g O₂ x 1 mol O₂ / 32 g = 0.375 moles O₂

0.375 moles O₂ x 2 moles V₂O₅ / 5 mols O₂ = 0.15 moles V₂O₅

Answer 2

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