How do I find the length of the side of the base, the slant height, and height of a square based pyramid with two given measurements?

Question

How do I find the length of the side of the base, the slant height, and height of a square based pyramid with two given measurements? The two measurements are S.A = 1200m and L.A= 624m.

Answer 1

SA = LA + area of base (B)

1200 = 624 + B

B = 576

square pyramid, so length of side is sqrt(B) = 24

LA = 1/2 * slant height * perimeter

624 = 1/2 * slant height * 96

slant height = 13

height^2 + half side ^2 = slant height^2

height^2 + 144 = 169

height = 5

Answer 2

height of pyramyd = 624m.

slant height of pyramid= 1200m.

it makes right angled triangle from center of square base

length of base = √ 1200² - 624² = 1024.9995m.

it is equal to half of side of square base . length of full side

= 1024.9995 × 2 = 2050m .