I got c correct me if i'm wrong

Question

Consider the following unbalanced equation: Al4C3 + H2O → Al(OH)3 + CH4 How many moles of Al(OH)3 will be produced when 0.469 mol of CH4 is formed?

a. 0.352 mol b. 0.625 mol c. none of these d. 0.469 mol e. 0.156 mol

Answer 1

Your answers seems to be INCORRECT.

Looking at the balanced equation Al₄C₃ + 12H2O ==> 4Al(OH)₃ + 3CH₄

and using dimensional analysis, we see that...

0.469 moles CH₄ x 4 mols Al(OH)₃ / 3 mols CH₄ = 0.625 mols Al(OH)₃ will be produced (Answer b)